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Debora [2.8K]
3 years ago
14

The number of bagels sold daily for two bakeries is shown in the table: Bakery A Bakery B 45 48 52 42 51 25 48 45 61 57 34 10 55

43 46 46 Based on these data, is it better to describe the centers of distribution in terms of the mean or the median? Explain. Mean for both bakeries because the data is symmetric Median because the distribution is not symmetric for both bakeries Mean for Bakery B because the data is symmetric; median for Bakery A because the data is not symmetric Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric
Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

a b

Step-by-step explanationbihdf bi f

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$38.3

Step-by-step explanation:

Baseball = $7.2

Basketball = $45.5

45.5-7.2 = 38.3

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Which of the following is an example of an aerobic activity that improves cardiovascular endurance?
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a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
2 years ago
How do you do this and what is it called
vivado [14]

Answer:

factorization

Step-by-step explanation:

it is called factorization try to go through your mathematics note book you would understand

5 0
3 years ago
Find the measure of angle x in the figure.
Ghella [55]

Answer:

x = 125°

Step-by-step explanation:

There are 7 angles in this shape. The sum of the angles in a shape like this is calculated using a formula.

Total of angles

= (n - 2)•180°

Put in 7, because there are 7 angles.

= (7 - 2)•180°

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= 900°

So the total of the angles should be 900°. We know all of the angles except one.

900° = 123°+129°+128°+128°+132°+135°+ x

900° = 775° + x

Subtract 775.

125° = x

The missing angle is 125°.

4 0
2 years ago
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