Question

And right triangle sin (40 - x)° equals cos(3x)° degrees what is the value of x.

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

$\qquad \sf \dashrightarrow \: \sin(40 - x) = \cos(3x)$

$\qquad \sf \dashrightarrow \: \cos\{90 - (40 - x ) \} = \cos(3x)$

$\qquad \sf \dashrightarrow \:90 - (40 - x) = 3x$

$\qquad \sf \dashrightarrow \:90 - 40 + x = 3x$

$\qquad \sf \dashrightarrow \:3x - x = 50$

$\qquad \sf \dashrightarrow \:2x = 50$

$\qquad \sf \dashrightarrow \:x = 25 \degree$