Question

P(x)=x^2-2x-8 and q(x)=x^2-5x+14 what are the zeros of p(x) +q(x)?

Answer 1

X^2 - 2x - 8 = 0
(x - 4)(x + 2) = 0

x = -2, 4 Answer

x^2 - 5x + 14
(x - 7)(x + 2) + 0

x = -2, 7   Answer