If you represent the coordinates on the axis you will notice that the coordinates of the fourth vertex of the rectangle is (9,7)
Asssuming blanks are plus
5(x+1)=4(x+8)
distribute
a(b+c)=ab+ac
5(x+1)=5x+5
4(x+8)=4x+32
5x+5=4x+32
minus 4x from both sides
x+5=32
minus 5 from both sides
x=27
To simplify things, one could just use differentiation with exponents.
y= 1/(p +ke^p)= (p + ke^p)^-1
dp/dy = -1 - ke^p
Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
- is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:
The probability of both failing the test and being unfit is:
Hence, the conditional probability is:
0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287
Look for key words in this problem. 3 EQUAL sized roasts. So they want you to have them equally in each one. Get it?