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2 years ago

Find the length of the diagonal, round to the nearest tenth (( please answer, ill give brainliest))

Mathematics

1 answer:

Lilit [14]2 years ago

6 0

Answer:

Length of diagonal in the first top figure is 13 yd

Okay for this one, the formula of a diagonal in a cuboid is the root of sum of squares

length, breadth and height

D = root of 12^2 + 4^2 + 3^2

D = root of 144 + 16 + 9

D = root 169

D = 13yd

Length of diagonal in the bottom figure is 10.77 which is 10.8m

For this one, you have to find the diameter of base first

Since radius of the base is 5 diameter = 10

Since its a right angled triangle, Hypotenuse square = sum of sides square

Diagonal^2 = 10^2 + 4^2

D^2 = 100 + 16

D^2 = 116

D = root 116

D = 10.77

D = 10.8 m

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JulsSmile [24]

Answer:

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5 0

2 years ago

The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked

Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=47-1=46$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$525-2.01\frac{75}{\sqrt{47}}=503.01$

$525+2.01\frac{75}{\sqrt{47}}=546.99$

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:

$ME=t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{t_{\alpha/2} s}{ME})^2$ (2)

The critical value for 95% of confidence interval is provided, $t_{\alpha/2}=2.01$ from part a, replacing into formula (2) we got:

$n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464$

So the answer for this case would be n=464 rounded up to the nearest integer

8 0

3 years ago

Can someone help me?

Whitepunk [10]

Answer:

Purple -3 is the answer

Step-by-step explanation:

We start by opening the bracket

That would be;

x-x-3

= 0-3 = -3

So selecting the correct option, we can see that our answer is purple

5 0

2 years ago

Does anyone know this ?? i’m super confused :(

LuckyWell [14K]

Need some Some big brain so here take some

8 0

3 years ago

Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a

vlabodo [156]

The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:

We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.

Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4

4 does not equal -8, therefore

The limit does not exist

4 0

2 years ago

Find the length of the diagonal, round to the nearest tenth (( please answer, ill give brainliest))​

Find the length of the diagonal, round to the nearest tenth (( please answer, ill give brainliest))