Do you remember how to find the area of a circle ?
Big Fat Hint: The area of a circle is (pi) x (its radius)² .
Can you find the area of the big circle ... the one with radius = 18 m ?
Do that. The whole big circle, just as if there was nothing inside it, and
no shaded region.
I'll wait.
Now, can you find the area of the small circle ... the one with radius = 12 m ?
Do that.
I'll wait.
The area of the shaded region is just
(the area of the big circle) minus (the area of the small circle) !
I got 180 pi or roughly 565.2 m². I could be wrong. You should check it.
For .4 shade 4 squares, for .04 shade a bit less than half a square
He gave away 9 (20 x (3/7) =9) so 21-9=12
Answer:
IDK try searching it up
Step-by-step explanation:
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
