Question

Will give brainliest, thanks, and 5 stars! LOTS OF POINTS! 50 POINTS!

Answer 1

Answer in order:

False

True

False

False

False

False

False

True

True

Step-by-step explanation:

All of the solutions to the equation$3x^2 - 12 = 0$are x = 12 and x = -12

Solve:

Common factor - $3(x^2-4)=0$

Divide both sides

$x^2-4=0$

Use the quadratic formula

$x=\sqrt{4,x}=\sqrt{-4$

x = 2, x = -2

Thus, This is false..

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There are two unique solutions to the equations (x-3)^2 = 16

one variable in matrix = one possible value.

Therefore, x = 7, x = -1

Hence this is True

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The solutions for the equation 2(x-3)^2-18 = 0 are x = 6 and x = 0

$2x^3-18x^2+54x-72=0$

$x=5.080084$

Hence this is false

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The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Add both sides by 8

2(x-5)^2-8+8=0+8

2(x-5)^2=8

(x-5)^2=4

x = 7, x = 3

Hence, this is false

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The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

$(x+3)^2=17$

$x=\sqrt{17-3,}=-\sqrt{17}-3$

Hence this is false.

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The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

$(2x-1)^2=9$

x=2, x = -1

Hence this is false.

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The only solution for equation (2x-1)^2-49=0 is x = 4

$(2x-1)^2=49$

x = 4, x = -3

Hence, this is false

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The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

$3(x+2)^2=3$

$(x+2)^2=1$

x = -1, x = -3

Hence, this is true

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The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x  = -6

Add 180 to both sides

$5x^2-180+180=0+180$

$5x^2 = 180$

$x^2 = 36$

$x=\sqrt{36},x=-\sqrt{36}$

x = 6, x = -6

Hence, this is true.

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[RevyBreeze]