Question

Thirty percent of a magazine's subscribers are female. A random sample of 50 subscribers Answer the following questions using Excel: (using standart devision of 0.0648)
a. What is the probability that the proportion of females from this sample is at most 0.25
b. What is the probability that the proportion of females from this sample is between 0.22 and 0.28
c. What is the probability that the proportion of females from this sample is within 0.03 of the population proportion?

Answer 1

Based on the mean of the subscribers, the sample size, and the standard deviation, the probability of females being at most 0.25 is 0.2202.

The probability that they are between 0.22 and 0.28 is 0.2703.

The probability that they are within 0.03 of the population proportion is 0.3566.

What is the probability that they are at most 0.25?

Using Excel, we shall assume that the distribution is normally distributed.

We can therefore use the NORM.DIST function:

=NORM.DIST(0.25,0.3,0.0648,TRUE)

= 0.2202

What is the probability that they are between 0.22 and 0.28?

=NORM.DIST(0.28,0.3,0.0648,TRUE) - NORM.DIST(0.22,0.3,0.0648,TRUE)

= 0.2703

What is the probability that they are within 0.03 of the population proportion?

X high = 0.30 + 0.03

= 0.33

X low = 0.30 - 0.03

= 0.27

= NORM.DIST(0.33,0.3,0.0648,TRUE) - NORM.DIST(0.27,0.3,0.0648,TRUE)

= 0.3566.

Find out more on probability at brainly.com/question/1846009.