Find slope (y2-y1)/(x2-x1)
Pick points: (1,10) , (2,8)
(8-10)/(2-1) = -2/1 = -2
Y = -2x + b
10 = -2 + b, b = 12
It would be the first response
12 = initial while -2 is rate of change
15x + 28y = 116
x + y = 6
that would be ur system of equations
I don't exactly know what a net is, but I can figure out the surface area (maybe). When you put this pattern together, you have to make a couple of assumptions.
First of all the 2 triangles are connected to a base that's 8 by 13.
Base
The area of the base = 8 * 13 = 104 square feet.
Two Triangles.
The area of any triangle is
Area = 1/2 b * h
Area = 1/2 *12 * 5
Area = 30 square feet. There are 2 triangles so ...
The total area of both is 60 square feet.
Overlap
Now we come to the tough part. how big is it from the first dotted line to the second one?
The answer is 5. But why? Well the 5 comes from the the length of the side that has to be covered by this pattern. The 5 is part of the triangle.
How far across is the dotted line? The answer is 8. Why again? That's the width of the whole prism or pattern.
So the area between the two dotted lines is 5 * 8 = 40
Finally the area over the 12.
The question is how far is it from the second dotted line to the last boundary? The answer is 12. And it's width is 8
So the area = 12 * 8 = 96
Total area
96 + 60 + 40 + 104 = 300 square feet.
Answer:
less mass
Step-by-step explanation:
The product has less mass because some of its mass got burned. Hope this helps!
Answer:
<h2>
A(-2, 2) and B(6, 10)</h2>
Step-by-step explanation:
Given the equation of a line y = x + 4 and equation of a circle as
( x − 3 )² + ( y − 5 )² = 34, if the line and the circle intersect at points A and B, to get this points, we will substitute the equation of the line into that of the circle as shown;
We will have to expand the equation of the circle first before making the substitute.
( x − 3 )² + ( y − 5 )² = 34
x²-6x+9+y²-10y+25 = 34
x²+y²-6x+-10y+34-34 = 0
x²+y²-6x+-10y = 0
Substituting y = x+ 4 into the resulting expression;
x²+(x+4)²-6x+-10y = 0
x²+x²+8x+16-6x+-10(x+4) = 0
x²+x²+8x+16-6x+-10x-40 = 0
2x²-8x-24 = 0
x²-4x-12 = 0
(x²-6x)+(2x-12) = 0
x(x-6)+2(x-6) = 0
x+2 = 0 and x-6 = 0
x = -2 and 6
when x = -2;
y = -2+4
y = 2
when x = 6
y = 6+4
y = 10
The coordinates of the point of intersection are A(-2, 2) and B(6, 10).
