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2 years ago

100 POINTS! Select the correct answer. Which system of equations is represented by this graph?

Mathematics

2 answers:

BARSIC [14]2 years ago

5 0

Answer:

Step-by-step explanation:

Remember, the equation of slope-intercept is y=mx+b

We see that for A, that the first equation's slope is -2/3. That means we are going to move down two and left five. The reason why we are going down is that the slope is negative. We also know that our y-intercept is -4. So we first plot the point (0,-4). Then we move down two and left five. We apply the same knowledge with the second equation. When we plot both equations, we get the same exact graph as the picture.

kompoz [17]2 years ago

3 0

Answer:

The answer is choice A!

Step-by-step explanation:

if my answer if correct can u please mark this brainliest :) :) :)

have a great day

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An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that $n = 48$

The probability that any integrated circuit is defective is 0.01.

This means that $p = 0.01$

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173$

0.6173 = 61.73% probability that the product operates.

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2 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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