3 pounds to 18 ounces

Mathematics

1 answer:

Allisa [31]2 years ago

4 0

Answer:

divide the pounds to get 18 ounces

Step-by-step explanation:

i think?

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Answer in simplest form?3/8+5 1/2

Delvig [45]

Convert 5 1/2 ro improper fraction so 10/2
3/8 + 10/2
Then convert 10/2 into 40/8 by multiplying bu four so they have the same denominator
3/8 + 40/8 =43/8

7 0

3 years ago

Convert 10 miles per hour to meters per second. Round to the nearest tenth.

LUCKY_DIMON [66]

Answer:

4.5 meters/second

Step-by-step explanation:

First we can find out how to convert one hour into seconds, which will be 3600 seconds. Now we have to figure out how many meters are in a mile, and multiply that by 10 to figure out how many meters are traveled per 3600 seconds (hour). The amount of meters in a mile is about 1609.34, which means the number of meters in 10 miles is 16093.4 meters. Now we know that 10 miles per hour is equal to 16093.4 meters per 3600 seconds. The last thing we need to do is divide the amount of meters per 3600 seconds by 3600 to find the amount of meters traveled in one second. This means we have to do 16093.4/3600 which is about 4.47, which rounded to the nearest tenth is 4.5.

4 0

3 years ago

Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a

Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

$P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}$

(a). Exactly one face up is red.

The odds of only the first die being red are:

$P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}$

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

$P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}$

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

$P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}$