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3 years ago

7

Let f(x) = 9x − 2 and g(x) = −x + 3. Find f(g(x)).

1 answer:

Tanya [424]3 years ago

5 0

Since g(x) is -x-3, replace g(x) with -x-3, f(g(x))=f(-x+3)
Since the x in f(x) is replaced with -x-3, f(-x-3)=9(-x+3)-2 which is -9x+27-2 which =-9x+25, so... your answer in C

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nexus9112 [7]

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3 years ago

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2 years ago

[23-3] + [6x9 how to solve it

blsea [12.9K]

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Step-by-step explanation:

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2 years ago

Convert 5 square root of a into exponential form?

stich3 [128]

Answer:

The answer is: " $5a^\frac{1}{2}$ " .

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Step-by-step explanation:

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We are asked to convert "5 square root of a" ; into "exponential form".

Note that "5 square root of a" ;

or; " 5 root a " ;

means: " 5 times the {square root of the variable, "a" };

or : " 5 multiplied by the {square root of the variable, "a" }.

_______________________________________________

This can be written as: " $5\sqrt{a}$ " .

_______________________________________________

<u>Note the following property of exponents</u>:

$\sqrt[n]{a^m} = (\sqrt[n]{a})^m = a^m^n$ .

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So; to write: " √a " ; <u> </u><em><u>as an exponent</u></em><u> </u> :

______________________________________________

<u>Note</u>:

" $\sqrt{a} = \sqrt[2]{a} = \sqrt[2]{a^1} = (\sqrt[2]{a})^1 = a^\frac{1}{2}$ " .

_______________________________________________

<u>So</u>:

" $\sqrt{a} = a^\frac{1}{2}$ " ;

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<u>And</u>:

________________________________________________

" $5\sqrt{a} = 5a^\frac{1}{2}$ " .

________________________________________________

→ The answer is: " $5a^\frac{1}{2}$ " .

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Hope this helps!

Best wishes in your academic endeavors

— and within the "Brainly" community!

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6 0

2 years ago

Find the length of the line segment whose endpoints are (-5,6) and (6,6)

umka21 [38]

Answer: 11 units

Step-by-step explanation:

Use the distance formula: $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

$(x_{1}, y_{1})=(-5, 6)\\(x_{2}, y_{2})=(6, 6)\\\\\sqrt{(6-(-5)^{2}+(6-6)^{2}} =\sqrt{(11)^{2}+(0)^{2}} =\sqrt{121+0}=\sqrt{121}=11$

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2 years ago