Answer:
{-2, -14, -26, -50}
Step-by-step explanation:
The range of the function is the function evaluated at each point of the given domain. So to find the range of the function we need to find the value of the function for each point in the domain:
- For x = -8




The first value of the range of the function is -2
- For x = -2




The second value of the range is -14
- For x = 4




Th third values of the range is -26
- For x = 16




The fourth and last value of the range is -50
Now we can put all the values of the range together
The range of the function is {-2, -14, -26, -50}
Answer:
The second regon
Step-by-step explanation:
2.) Given: There are 30 students. 24 are wearing sneakers.
Work: We can figure this out by finding the exact percentage of sneaker-wearers in the class.
To find the percentage, you do 24/30. 24/30 is equal to 80%.
Answer: Joe is wrong. The percentage of students wearing sneakers is 80% and not 70%.
3.) Given: There are 40 people total. 2 women per 3 men.
Work: 2:3 women to men
If we multiply both by 10, we will get 50 people in total.
20:30 = 50
So we need to shrivel this down to 40 by taking out 5 on both sides of the ratio.
50 - 5 - 5 = 15:25 = 40
But the ratio need to be divisible by 2 because of the 2 women that are needed per 3 men. We can do this by moving over one human to the men’s side.
There are 14 women and 26 men. I didn’t use any of the strategies there listed because I don’t even remember what those are. I’m in grade 9. I would say that the ratio table works best because I just used ratios...
4.) Given: Find simplified fraction of silicon. 100%.
Work: Add all things up to find out the denominator for the fraction. They will equal 100.
So the fraction is 28/100.
We can divide this fraction by 4.
7/25
This is the simplified form.
Answer: 7/25
Answer:
c. 0.1391 < Ï < 0.2311
Step-by-step explanation:
The formula for Confidence Interval is given as:
Mean ± z × Standard deviation/√n
Z score for 98% confidence interval = 2.326
Mean = Significance level = 100% - 98%
= 2% = 0.02
Standard deviation = S=0.0165
n= 37
Hence,
Confidence Interval =
0.02 ± 2.326 × 0.0165/√37
0.02 ± 0.0063094687
Confidence Interval
0.02 - 0.0063094687
= 0.1391
0.02 ± 0.0063094687
= 0.2311
Hence, the Confidence Interval = (0.1391, 0.2311)
= c. 0.1391 < Ï < 0.2311
Answer:
<em>No, because two points with the same y value have different values.</em>
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