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Sidana [21]
3 years ago
15

Find the equivalent expression of 3+2(2p+4t)

Mathematics
1 answer:
NISA [10]3 years ago
7 0

Remember to follow PEMDAS, and to only combine terms with like variables.

First, distribute the 2 to all terms within the parenthesis:

2(2p + 4t) = 2(2p) + 2(4t) = 4p + 8t

3 + 4p + 8t, or (D), is your answer choice, for it cannot be simplified anymore.

~

You might be interested in
Square root 7x+16 +4=x
gavmur [86]
1     Simplify 7x+16+47x+16+4 to 7x+207x+20<span>    7x+20=x<span>7x+20=x</span></span>
2     Subtract 7x from both sides<span>    20=x-7x<span>20=x−7x</span></span>
3 Simplify <span>x-7x<span>x−7x</span></span> to <span>-6x<span>−6x</span></span>
<span>20=-6x<span>20=−6x</span></span>
4     Divide both sides by −6    -20/6=x
5     Simplify 20/6 to 10/3     -10/3=x
6     Switch sides
    x=-10/3<span><span><span>     </span></span></span>
6 0
3 years ago
Studio fee:$8 per hour <br> Vase:$10
aleksandrvk [35]

Answer:

4.5 hours

Step-by-step explanation:

So, let's write a function p(x) which represents the total cost.

Let's let x represent the amount of hours.

The cost of a piece is a constant 10.

And there is a $8 fee per hour. In other words:

p(x)=8x+10

We spent a total of $46.

So, substitute in 46 for p(x) and solve for x:

46=8x+10

Subtract 10 from both sides:

36=8x

Divide both sides by 8:

x=36/8

Reduce:

x=4.5

So, we spent about 4.5 hours.

8 0
3 years ago
Factor 20r+60t to identify the equivalent expressions.
FrozenT [24]

20r + 60t

The greatest common factor we can factor from both of these terms is 20.

20(r + 3t). This is the final answer.

6 0
3 years ago
Help please I don’t get it
Nutka1998 [239]

Answer:

LP = 15

Step-by-step explanation:

LM = LP ( isosceles triangle sides will be equal )

10x - 5 = 7x + 1

Transpose to find the value of x

10x -7x = 1 + 5

3x = 6

x = 6/3

x = 2

now put 2 instead of x

10x - 5

10 (2) - 5

20 - 5

15

LP = 15

7 0
3 years ago
The length of a rectangle is one foot more than twice its width if the area of the rectangle is 300 ft^2 find the dimensions of
umka21 [38]
Let's say the length is L, and the width is W
L is one foot more than 2W, so L=1+2W
the area of the rectangle: A=L*W=300
replace L with 1+2W: (1+2W)*W=300 =>2W^2+W-300=0
solve the quadratic equation: (W-12)(2W+25)=0
W=12 or W=-12.5 (impossible)
so the width is 12, and the length is L=1+2*12=25

please refer to this website for how to factor a quadratic equation
http://www.purplemath.com/modules/factquad.htm

7 0
3 years ago
Read 2 more answers
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