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2 years ago

(02.01 LC) need help asap

Mathematics

1 answer:

o-na [289]2 years ago

7 0

The coordinate of H' from the transformation (x, y) → (x + 8, y + 5) is H'(4, 8)

<h3>What is transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

Given the translation of figure EFGHK using the rule (x, y) → (x + 8, y + 5). If point H is at (-4, 3), the coordinate of H' would be at (4, 8)

The coordinate of H' from the transformation (x, y) → (x + 8, y + 5) is H'(4, 8)

Find out more on transformation at: brainly.com/question/4057530

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The midpoint of segment AB is (-7, 10) and endpoint A is located at (3, -1). Find the other endpoint B. Show all work.

dusya [7]

Answer:

$B(-17,21)$

Step-by-step explanation:

The midpoint of two points is the average of the x coordinates and the average of the y coordinates.

Given

A(3, -1)

and we let the other end point B be B(x,y)

and midpoint is (-7,10)

So, the average of 3 and x is -7, and

the average of -1 and y is 10

We can solve for x first:

$\frac{3+x}{2}=-7\\3+x=2*-7\\3+x=-14\\x=-14-3\\x=-17$

and now solving for y:

$\frac{-1+y}{2}=10\\-1+y=2*10\\-1+y=20\\y=20+1\\y=21$

So, the other point B is:

$B(-17,21)$

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2 years ago

Read 2 more answers

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

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3 years ago

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Simplified:

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3 years ago

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Norma-Jean [14]

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Step-by-step explanation:

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