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Basile [38]
3 years ago
14

there are 36 cans of beans and 48 cans of corn. the display designer wants an equal number of each vegetables in each row. what

is the greatest number of cans of corn that can be in each row?
Mathematics
1 answer:
Basile [38]3 years ago
5 0
4 cans of beans and 3 cans of corn
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Covert 3.92 into a mixed number in simplest from
Kobotan [32]
First, take three off it, because that will form the whole-number part:
3.92 = 3 + 0.92

Next, read off the place value of the last digit. The 2 is in the 'hundredths' column, which means that 0.92 = 92/100:
3.92 = 3 + 92/100

Finally, simplify 92/100 by dividing top and bottom by 4 to get 23/25. Then, shove it all together:
3.92 = 3 23/25
8 0
3 years ago
Read 2 more answers
Solve the following system of equations using the substitution method.
sergey [27]

Answer:

y=1; x=2

Step-by-step explanation:

Substitution:

x=2y

2x+5y=9

=> if x=2y, plug in the x value into other equation, so

----------------------------------------------------------------------------

2(2y)+5y=9

4y+5y=9

9y=9

y=1

You have the Y value, so now solve for X

-----------------------------------------------------------------------

plug in y value to x=2y

so x=2(1)

x=2

5 0
3 years ago
Can someone please help me out with this? I will give brainliest if it lets me!
AlekseyPX

Answer: D is the correct answer

7 0
3 years ago
Please help mee l don’t understand new topic please
jasenka [17]

Answer to first four-

first one- 2f+2f=60

4f=60

f=15

second one-18+2d=38

2d=20

d=10

(short side is 9)

third one-2a+a+5+a+5=26

4a+10=26

a=4

long side is 9

short side is 8

fourth one-3xy+3xy+xy=63

7xy=63

xy=9

long side is 27

4 0
2 years ago
Given h(x) = 3x - 3, find h(3).
Daniel [21]

Answer:

<h2>h(3) = 6</h2>

Step-by-step explanation:

h(x) = 3x - 3

To find h(3) , substitute the value of x that's 3 into h(x). That is for every x in f (x) replace it with 3

We have

h(3) = 3(3) - 3

= 9 - 3

We have the final answer as

<h3>h(3) = 6</h3>

Hope this helps you

4 0
3 years ago
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