To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
Trying to solve this leads to an absurdity, so No Solution.
Step-by-step explanation:
5x+12=5x−7
Lets attempt to solve:
Subtract 5x from both sides
5x - 5x + 12 = 5x - 5x - 7
0 + 12 = 0 - 7
12 = -7
This is absurd so there is no solution.
It’s a I think but I’m not sure
What type of graphs
if it is a bar graph look at the hights or the ranges
if it is a line graph look at how much it drops or how much it raises by
if it is just any kind of graph look at y and x axis how much does it skip
Answer:
<em>x < 2</em>
<em />
Step-by-step explanation:
3x - 2 < 4
<em> + 2 | + 2</em>
------------------
3x < 6
↓
<em>(3x) / 3 < 6 / 3</em>
↓
x < 2
