Answer:
or
Step-by-step explanation:
Use the quadratic formula.
or
Answer: No
Currently we don't have enough information to prove this quadrilateral is a parallelogram. One piece of information that would be useful would be if the other diagonal is bisected. If that's the case, then we have a parallelogram (we would first prove the triangles congruent and then use the corresponding congruent angles to set up the parallel lines). Unfortunately, we only know about one diagonal being bisected, but not both, so we don't have enough info.
With the round toward even rule, 0.5 rounds to zero.<span>
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A point belongs to the x axis if its y coordinate equals zero.
The points on a graph are in the form , so these points are on the x axis if and only if
In this case, we have
You can observe that your expression is actually a squared binomial: using
you can notice that
So, you have
Now, how we decide if this function "touches" or "passes through" the x-axis at x=7? Well, since our function is a square, it is never negative. So, this graph can't cross the x-axis, but rater touch it from above. The parabola has a U shape, and the point of minimum lies on the x axis.
So, the graph touches the x axis at x=7.
18 cups because every pint equals 2 cups