Can u help me? thank you
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Answer:
25150
Step-by-step explanation:
First, we have to see that this is an arithmetic sequence... since to get the next element we add 5 to it. (a geometric sequence would be a multiplication, not an addition)
So, we have a, the first term (a = 4), and we have the difference between each term (d = 5), and we want to find the SUM of the first 100 terms.
To do this without spending hours writing them down, we can use this formula:
If we plug in our values, we have:
S = 50 * (8 + 495) = 50 * 503 = 25150
In 90 minutes the population to grow to 700 organisms.
Given that,
A strand of bacteria has a doubling time of 15 minutes.
If the population starts with 10 organisms.
We have to determine,
How long would it take for the population to grow to 700 organisms?
According to the question,
A strand of bacteria has a doubling time of 15 minutes.
If the population starts with 10 organisms.
In 15 minutes strand of bacteria has a doubling time the population starts with 10 organisms.
In 15 minutes 20 bacteria for the population to grow.
In 30 minutes strand of bacteria has a doubling time the population starts with 20 organisms.
In 30 minutes 40 bacteria for the population to grow.
In 45 minutes strand of bacteria has a doubling time the population starts with 40 organisms.
In 45 minutes 80 bacteria for the population to grow.
In 60 minutes strand of bacteria has a doubling time the population starts with 80 organisms.
In 60 minutes 160 bacteria for the population to grow.
In 75 minutes strand of bacteria has a doubling time the population starts with 160 organisms.
In 75 minutes 320 bacteria for the population to grow.
In 90 minutes strand of bacteria has a doubling time the population starts with 320 organisms.
In 90 minutes 640 bacteria for the population to grow.
In 120 minutes strand of bacteria has a doubling time the population starts with 640 organisms.
In 120 minutes 1280 bacteria for the population to grow.
Hence, In 90 minutes the population to grow to 700 organisms.
For more details refer to the link given below.