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4 years ago

What is the height, X, in the triangle below?

Mathematics

1 answer:

Radda [10]4 years ago

6 0

There's a formula from similar triangles .

x^2=5*10
so, x=5√2

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Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).

Flura [38]

Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)

we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5

slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1

slope=-1

4 0

3 years ago

Read 2 more answers

Which of the following correlation coefficients would represent the strongest correlation? -0.9 -0.16 0.04 .78

kolezko [41]

Answer:

0.4 would represent the strongest correlation.

Step-by-step explanation:

Generally, a value of r greater than 0.7 is considered a strong correlation. Anything between 0.5 and 0.7 is a moderate correlation, and anything less than 0.4 is considered a weak or no correlation

8 0

3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago

What is the value of 4 x 3 divided by (12 divided by2)^2

Digiron [165]

Answer:0.333

Step-by-step explanation:

5 0

3 years ago

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Find an equation for the perpendicular bisector of the line segment whose endpoints are

Degger [83]

Answer:

y = -2/3x - 11/3

Step-by-step explanation:

7 0

3 years ago