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hoa [83]
2 years ago
12

Can you help me out?

Mathematics
1 answer:
slavikrds [6]2 years ago
6 0

1) Unanswered (Sorry)

2) Find the cost of a four-line ad
x = 4 \\Therefore,\\c(4) = 30

3) Find the cost of a ten-line ad
x = 10\\Therefore,\\c(10) = 30 + 5(x - 4)\\c(10) = 30 + 5x - 5(4)\\c(10) = 30 + 5x - 20\\c(10) = 30 + 5(10) - 20\\c(10) = 30 + 50 - 20\\c(10) = 60


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In this diagram, BAC~EDF. If the area of BAC=15 in2, what is the area of EDF? 4, 5.
lesya692 [45]

Answer:

9.6 square inches.

Step-by-step explanation:

We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.

First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:

\displaystyle 5 k = 4

Solve for the scale factor <em>k: </em>

<em />\displaystyle k = \frac{4}{5}<em />

<em />

Recall that to scale areas, we square the scale factor.

In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.

Hence, the area of ΔEDF is:

\displaystyle \Delta EDF = \frac{16}{25}\left(15\right) = 9.6\text{ in}^2

In conclusion, the area of ΔEDF is 9.6 square inches.

5 0
3 years ago
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eimsori [14]

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8) B. 70

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3 0
3 years ago
At a store, customers are randomly selected to participate in a survey. On Friday, there were 500 customers at the store. Out of
Svetlanka [38]
Divide the number of people selected by the total number of people.

90/500 = .18

This means that 18% of the customers were selected for the survey.

If the probability is the same on Saturday, then we can multiply the expected customers by our .18

700 x .18 = 126

126 should be selected for the survey on Saturday.
7 0
3 years ago
A production manager randomly sampled production lines at a factory that produces automobiles. She wanted to find out how many p
Elena-2011 [213]

Answer:

The confidence interval for the proportion of production lines that caused defects is (0.07, 0.09).

Step-by-step explanation:

A confidence interval for a population proportion is a function of the sample proportion and the margin of error.

The interval has two bounds, a lower bound and an upper bound.

The lower bound is the sample proportion subtracted by the margin of error.

The upper bound is the margin of error added to the sample proportion.

In this problem, we have that:

Sample proportion 0.08

Margin of error 0.01

0.08 - 0.01 = 0.07

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The confidence interval for the proportion of production lines that caused defects is (0.07, 0.09).

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3 years ago
28 + 56t + 28w equivalent expressions
irina [24]

Answer:

28(1+2t+w)

Step-by-step explanation:

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