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Nastasia [14]
3 years ago
6

The rule for the number of fish in a home aquarium is 1 gallon of water for each inch of fish length. Marta's aquarium holds 39

gallons of water and Hank's aquarium hold 51 gallons of water. The aquarium holds two types of fish, fish A and fish B. If Marta bought 3 of fish A and 2 of fish B, and Hank bought 3 of fish A and 4 of fish B, how long is fish A and how long is fish B?
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer: Fish A: 9 inches ; Fish B: 6 inches

Step-by-step explanation:

This can be turned into a systems of equation, where x equals the length of fish A and y equals the length of fish B:

3x + 2y = 39 → -3x - 2y = -39

3x + 4y = 51 → 3x +4y = 51

Combine: 0 + 2y = 12 → y = 6 inches.

Plug back in: 3x + 2(6) = 39 → 3x = 27 → x = 9 inches.

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Is (2,4) a solution of 3x - y = 2?
guajiro [1.7K]

yes because when filling in the unknown (3*2-4=2) gets you the answer of 2.

7 0
3 years ago
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PLEASE HELP GIVING 20 PTS!!!!!! For circle H, JN = 3, NK = x, LN = 2, and NM = 6. Solve for x. PLEASE HEEELLLLPPPPPPP!!!!!!!
Marina CMI [18]

Answer:

x=9

Step-by-step explanation:

when two chords intersects each other, then the product of their segments is equal.

JNxNK = LN x NM

3 *x = 2 * 6

x = (3*6)/2 = 18/2 = 9

5 0
3 years ago
Make n the subject of m= 4n-gn+1
Misha Larkins [42]

Answer:

n = (m-1)/(4-g)

Step-by-step explanation:

m= 4n-gn+1

Subtract 1 from each side

m-1= 4n-gn+1-1

m-1 = 4n -gn

Factor out n

m-1 = n(4-g)

Divide each side by (4-g)

(m-1)/(4-g) =  n(4-g)/(4-g)

(m-1)/(4-g) =  n

n = (m-1)/(4-g)

6 0
3 years ago
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Evaluate the expression 263 + 5 when b = 3.<br> 263 +5 = 2(3): +5<br> =
ExtremeBDS [4]

Given:

The expression is:

2b^3+5

To find:

The value of the given expression when b=3.

Solution:

We have,

2b^3+5

Substituting b=3 in the above expression, we get

2b^3+5=2(3)^3+5

2b^3+5=2(27)+5

2b^3+5=54+5

2b^3+5=59

Therefore, the value of given expression at b=3 is 59.

7 0
3 years ago
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A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9​, and the sample stand
yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

H_0:\mu=100 and H_1:\mu \:>\:100 (claim)

<u>Step 2</u>: Calculate the test value.

t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }

\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value  is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for \alpha=0.05 and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0
4 years ago
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