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pav-90 [236]
2 years ago
11

Fourth Grade Memory Jogger Week 5 I need helppppp

Mathematics
1 answer:
o-na [289]2 years ago
3 0

Answer:

I can help you what you need help with

Step-by-step explanation:

You might be interested in
Convert -2x+6y=-24 to slop intercept form​
Firlakuza [10]

Answer:

y= 1/3x - 4

Step-by-step explanation:

hope this helps

3 0
3 years ago
Which number is between 5/6 and 13
UNO [17]
1-12 is between 5/6 and 13.
6/6 is after 5/6 and that just equals 1
4 0
3 years ago
Construct a quadrilateral MINT such that MI= 5cm, IN = 6cm, NT = 7cm, TM=3cm and MN =9cm
Tems11 [23]

From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral

MINT can be drawn as shown in the attached image.

<h3>What are the steps for the construction of MINT?</h3>

The given dimensions of the quadrilateral MINT are;

MI = 5 cm

IN = 6 cm

NT = 7 cm

TM = 3 cm

MN = 9 cm

The side MN is a diagonal of MINT, therefore;

ΔMIN, and ΔMTN are triangles with a common base = MN

The steps to construct MINT are therefore;

  • Step 1; Draw the line MN = 9 cm.

  • Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.

  • Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.

  • Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.

  • Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.

  • Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.

Please find attached the drawing (showing the construction arcs) of the

quadrilateral MINT created with MS Word.

Learn more about types of geometric construction here:

brainly.com/question/785568

brainly.com/question/8607612

6 0
2 years ago
Can someone answer #9
In-s [12.5K]

Solution:

First i'm going to divide the graph into 3 parts. Linear, Quadratic and Horizontal graph.

<u>Linear:</u>

Slope=\frac{-2-0}{-4-(-2)}=1\\y=m(x-xo)+yo\\y=1x-(-2)+(-4)\\y=x-2 , x\leq-1

<u>Quadratic:</u>

f(x) = a(x-h)^{2} + k\\f(x)=(x-2)^{2}-7,-1\leq x\geq 6

<u>Horizontal:</u>

f(x)=7,x\geq 6

Answer:

f(x)=x-2 , x\leq-1\\f(x)=(x-2)^{2}-7,-1\leq x\geq 6\\f(x)=7,x\geq 6

<em>Hope this was helpful.</em>

8 0
3 years ago
X cube+6x-16=0
Aleksandr-060686 [28]

Answer:

  (b)  {-8, 2}

Step-by-step explanation:

The given equation

  x³ +6x -16 = 0

cannot be factored in integers. It has one irrational real root near x=1.759, and two complex roots.

__

Perhaps you want to factor ...

  x² +6x -16 = 0

  (x +8)(x -2) = 0

This has solutions x = -8 and x = 2 that make the factors be zero.

_____

<em>Additional comment</em>

"Cubed" refers to an exponent of 3.

4 0
2 years ago
Read 2 more answers
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