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Andrei [34K]
3 years ago
12

What is the surface area of this triangular prism rounded to the nearest tenth?

Mathematics
2 answers:
Korvikt [17]3 years ago
4 0

Answer:

The answer is B

Step-by-step explanation:

Stells [14]3 years ago
3 0

Answer:

23.876

Step-by-step explanation:

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The scale on a map is 1:500000 two towns are 7cm apart
Eddi Din [679]
7 x 500,000 = 3,500,000.

The towns are 3,500,000 units apart (I don't know what the cm were scale too, sorry.)
7 0
3 years ago
MIDDLE SCHOOL MATH DONT ANSWER IF YOU DONT KNO-<br> WILL GIVE BRAINLIEST
Juli2301 [7.4K]

Answer:

Radius is <u>2.8</u> Circumference is <u>17.584 or 17.6 Rounded to the nearest Tenths </u>

Step-by-step explanation:

1. Find circumference with the Formula <u>C=πd</u>

C=3.14 x 5.6

<u><em>C=17.584 or 17.6 Rounded to the nearest Tenths </em></u>

2. Radius is Always half of the Diameter.

5.6/2 = 2.8

<em><u>2.8 is your radius.</u></em>

3. If you want to check you work try the formula C=2πr to see if things checks out.

C=2 x 3.14 x 2.8

<u><em>C= 17.584 or 17.6 Rounded to the nearest Tenths </em></u>

<u><em /></u>

<u><em>Hope this Helps!</em></u>

3 0
2 years ago
Q - 8 as a verbal expression
sertanlavr [38]

Answer:

Step-by-step explanation:

An unknown number minus 8.

8 0
3 years ago
What is the length of the diagonal of a square with side length 50\sqrt{2} cm? Express your answer in simplest form.
jenyasd209 [6]

Answer:

Length of diagonal = 100 cm

Step-by-step explanation:

Given:

Side length of square = 50\sqrt{2}   cm

Using pythagorean theorem:

Sum of squares of sides = Square of Diagonal

( 50\sqrt{2} )^2 + ( 50\sqrt{2} )^2 = x^2

Solving for x:

x^2 = 10000\\x = 100

Therefore,

Length of diagonal = 100 cm

5 0
3 years ago
Let 0 be an acute angle of a right triangle. Evaluate the other five trigonometric functions of 0.
Ainat [17]

Answer:

1. Cos θ = 6√2 / 11

2. Tan θ = 7 / 6√2

3. Cosec θ = 11 / 7

4. Sec θ = 11 / 6√2

5. Cot θ = 6√2 / 7

Step-by-step explanation:

From the question given above, the following data were obtained:

Sine θ = 7 / 11

Next, we shall determine the adjacent of the right triangle. This can be obtained as follow:

Sine θ = 7 / 11

Sine θ = Opposite / Hypothenus

Opp = 7

Hypo = 11

Adj =?

Hypo² = Opp² + Adj²

11² = 7² + Adj²

121 = 49 + Adj²

Collect like terms

Adj² = 121 – 49

Adj² = 72

Take the square root of both side

Adj = √72

Adjacent = 6√2

1. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 11

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 11

2. Determination of Tan θ

Opposite = 7

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 7 / 6√2

3. Determination of Cosec θ

Sine θ = 7 / 11

Cosec θ =?

Cosec θ = 1 ÷ Sine θ

Cosec θ = 1 ÷ 7 / 11

Cosec θ = 1 × 11/7

Cosec θ = 11/7

4. Determination of Sec θ

Cos θ = 6√2 / 11

Sec θ =?

Sec θ = 1 ÷ Cos θ

Sec θ = 1 ÷ 6√2 / 11

Sec θ = 1 × 11 / 6√2

Sec θ = 11 / 6√2

5. Determination of Cot θ

Tan θ = 7 / 6√2

Cot θ =?

Cot θ = 1 ÷ Tan θ

Cot θ = 1 ÷ 7 / 6√2

Cot θ = 1 × 6√2 / 7

Cot θ = 6√2 / 7

7 0
3 years ago
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