Answer:
7 and 1
Step-by-step explanation:
Let the numbers be a and b.
<u>A positive number is 7 times another number:</u>
<u>If 3 is added to both the numbers then one of the new number becomes 5 by 2 times the other new number:</u>
<u>To solve this we substitute </u><u>a</u><u> with </u><u>7b</u><u> in the second equation:</u>
- 7b + 3 = 5/2 × (b +3) ⇒ multiplying both sides by 2
- 14b + 6 = 5b + 15 ⇒ collecting like terms
- 14b - 5b = 15 - 6
- 9b = 9
- b = 1 ⇒ solved for b
<u>Then, finding a:</u>
- a= 7b
- a=7*1
- a= 7 ⇒ solved for a
<u>So the numbers are</u> 7 and 1
Answer:
Step-by-step explanation:
A hole is an input value that makes both numerator and denominator equal to zero.
<u>Let's factorize the numerator and denominator:</u>
- 3x² - 108 = 3(x² - 36) = 3(x + 6)(x - 6)
- x² + 2x - 24 = x² + 6x - 4x - 24 = x(x + 6) - 4(x + 6) = (x - 4)(x + 6)
<u>We have same factor of x + 6:</u>
- x + 6 = 0
- x = - 6 is a hole
Answer:
9.25, 83^1/2, 8.7, 72^1/2, 2 From greatest to least
2, 72^1/2, 8.7, 83^1/2, 9.25 from least to greatest
Step-by-step explanation:
C is the right answer because the period should be pi/(1/3), so the answer is 3pi
