First pic
a. ΔMNK ≅ ΔRTP
b. TR ≅ NM
c. x = 7
3x - 1 = 20
3x = 20 + 1
3x = 21
x = 21 ÷ 3
x = 7
Second pic
SAS (Side-Angle-Side congruence)
SSS (Side-Side-Side)
Hope this helps
Answer:
(x+12)(x+5)
Step-by-step explanation:
Formula use: a²+bx+c
- Make one side equal to zero:
Original:
-7x-60 =x² +10x
New:
x² + 17x + 60
New:
(1)x x 60 = 60
- Find factors of 60 that when added, equal to 17.
New:
10 × 6, 60 × 1, 20 × 3, <u>5 × 12</u>, 4 × 15
5 times 12 equal 60, but when added equal to 17.
- Replace the 17 with 5 and 12
New:
x² + 5x + 12x + 60
- Break them off into two equations
New:
x² + 5x l 12x + 60
- Divide each equation into it's simpilest form. Make sure the numbers in the ( ) are the same.
New:
x(x + 5) l +12(x+5)
Answer:
<h3>Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)</h3>
Step-by-step explanation:
Given the expression
- 2 (x + 3) = - 10
The first step in solving the expression is to multiply both sides by -1/2 as shown;
-1/2(-2)(x+3) = -1/2(-10)
(x +3) = 1/2(10)
x + 3 = 5
x = 5-3
x = 2
Hence the correct option is Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)
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