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Makovka662 [10]
2 years ago
5

If f(x) = 1/9x-2, what is f^-1(x)?

Mathematics
1 answer:
gavmur [86]2 years ago
8 0

Answer:

9x-2

Step-by-step explanation:

f^-1(x)=1/f(x)=9x-2

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Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QR. QR = 12 QR = -12 QR = 28 QR = 56
vfiekz [6]
The midpoint divided a segment into two congruent lengths/segments.

So, QM = MR.

Set up the equation.

16 + x = 2(x+ 2)

16 + x = 2x + 4

12 + x = 2x

12 = x


Now, that you have the value of x, substitute it for the two equations.

QM = 16 + x

QM = 16 + 12

QM = 28


MR = 2(12+ 2)

MR = 2(14)

MR = 28


Find the whole length by of the line by adding the two segments. 28 × 2 = 56.

QR = 56
6 0
3 years ago
Help me with this ASAP!!!
joja [24]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
what is the rate of change for the linear relationship modeled in the table? x y −1 10 1 9 3 8 5 7 -1/2 0 1/2 2
Vesnalui [34]

Answer:

Rate of change for the linear relationship modeled is \dfrac{-1}{2}

Step-by-step explanation:

As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.

We know that, the slope of the line joining (x₁, y₁) and (x₂, y₂) is,

m=\dfrac{y_2-y_1}{x_2-x_1}

Putting the points as (-1, 10) and (1, 9), we get

m=\dfrac{9-10}{1-(-1)}

=\dfrac{9-10}{1+1}

=\dfrac{-1}{2}

Rate of change is the slope of the line joining all these points.

7 0
3 years ago
Read 2 more answers
find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on
enyata [817]

Let f(x)=\tan^{-1}x. Then f'(x)=\frac1{1+x^2}. Note that f(0)=0.

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n

This means that for |-x^2|=|x|^2, or -1, we have

\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}

Integrate the series to get

f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

6 0
3 years ago
Using the order of operations, what is the last calculation that should be done to evaluate
mel-nik [20]

200-(-2) is actually 200-1(-2)

So thats multiplication

Then its 200+2

So addition is the last calculation to be done.

7 0
3 years ago
Read 2 more answers
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