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meriva
2 years ago
7

How do I use the intermediate value theorem to prove every polynomial of odd degree has at least one real root?

Mathematics
1 answer:
Anon25 [30]2 years ago
3 0

Answer:

Step-by-step explanation:

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A set of 5 cards is labeled1-5.
kaheart [24]
1 car, 2 cars, 3 cars, 4 cars, 5 cars
4 0
3 years ago
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Which value of x is a solution to x³ = 216<br><br> A. 6<br> b.18<br> c.72<br> d.108<br> e.648
Morgarella [4.7K]
The answer is A. 6
6•6•6
5 0
3 years ago
And this question please?
defon

Answer:

this would be 5

Step-by-step explanation:

beacuse it has a different answer every time

6 0
3 years ago
Could someone please help
LiRa [457]
11 is the answer.

5+5 is 10
1/2 + 1/2 is 1
10+1 is 11
4 0
3 years ago
Please help me!
ale4655 [162]

By convention, the first term of a sequence starts with n = 1 instead of n = 0. This is so n = 1 matches with 1st, n = 2 matches with 2nd, and so on.

In contrast, the y intercept always occurs when x = 0. So something like y = 3x+5 has a y intercept of 5 when you plug in x = 0.

An arithmetic sequence like f(n) = 2n+7 has its first term when n = 1. So the first term would be f(1) = 2(1)+7 = 9 instead of 7 as Hank claims.

7 0
3 years ago
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