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AlexFokin [52]
3 years ago
13

What's the digit in the tenths place ​

Mathematics
1 answer:
Darya [45]3 years ago
5 0
Tenths is the digit in the tenths place. Like 0.1 being 1 tenth.
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Which congruence postulate proves that the two triangles are<br> congruent?
inna [77]
The answer is SSS since both triangles have equal sides the third one has to be congruent since they share the same line
8 0
3 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
Solve for z, wz-4/ 5z
saw5 [17]

x=\dfrac{wz-4}{5z}\\\\5xz=wz-4\\\\5xz-wz=-4\\\\z(5x-w)=-4\\\\z=-\dfrac{4}{5x-w}

7 0
3 years ago
A restaurant has 75% of its tables being used. Which ratio compares the used tables with all the tables in the restaurant?
Bogdan [553]
75%=75/100=75:100=3/4

4-3=1

1/4=tables not used.

1/4=25/100=25:100

So....25:75 = not used tables : used tables

Hoped I helped!
5 0
3 years ago
Read 2 more answers
Domain<br> Range<br> -3<br> 6<br> 5<br> 3<br> -2.<br> 1
uranmaximum [27]
Hello there!

Domain={-3,5,2}
Range={6,3,1}

Hope this helps

Have a great day/night
3 0
3 years ago
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