Answer:
C.
if (Math.sqrt(var) > 25)
{
System.out.println("large enough");
}
Explanation:
Analyzing each option:
(a): if (Math.sqrt(var) < 25)
The above condition uses < which means less than.
So, basically the condition checks if the square root of var is less than 25
This is not the required condition in the question
(b): if (Math.sqrt(2, var) > 25)
The above is an incorrect syntax of checking for square roots and it'll return an error when the program is run
To look for square root, make use of <em>Math.sqrt(var)</em>
<em></em>
(c): if (Math.sqrt(var) > 25)
As stated in the last statement of (b), the correct syntax to check for square root is <em>Math.sqrt(var) </em>and the condition above makes use of > which implies that if square root of var is greater than 25.
And if yes, it prints large enough
(d): if (Math.pow(var, 2) < 25)
This doesn't check for square root of var but rather it checks for var raise to power of 2.
So, from the analysis above;
Option c answers the question
