Answer:
so what is this uhhhhhhhhhh
<span>The statement that "Persons who have been given access to an installation can be counted on to be of no threat" is false. If they are not honest enough, they could become the dangerous staff the company could ever had because he or she has access to everything, files, information, etc. That is why, in selecting a person to be trusted with such responsibility, he or she undergoes an intensive training.</span>
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

⇒ t = 8.7*10⁻⁴ sec.
Answer:
all of them are responsibilities
Explanation:
Hello <span>Tacobell5401</span>
Answer: A client-server application that requires nothing more than a browser is called thin-client application
Hope this helps
-Chris