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2 years ago

8

The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) e^-x/1074 /107

4

1 answer:

love history [14]2 years ago

4 0

Can u add the picture please?? If u don’t mind

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8. The two triangles are congruent as suggested by their appearance. Find the value of all the variables. The

adelina 88 [10]

Answer: d is 53 degrees, c is 5, g is 13, e is 90 degrees, f is 37 degrees, b is 12 .

Step-by-step explanation:

Since they're congruent you just compare the two and replace them. You have the answers on both sides, they're just split up. So look at one side, then the other, and see what you can find. Repeat.

8 0

2 years ago

Read 2 more answers

Then p=3.<br> Use the equation k = 3n to find the value of k when n = 3.

Bad White [126]

Answer:

k = 9

Step-by-step explanation:

n = 3, so substitute 3 for n in the equation

k = 3(3)

k = 9

6 0

2 years ago

If line segment AB is 100%, what is the length of a line segment that is 200%?

professor190 [17]

2AB ...................

3 0

2 years ago

What is the result of subtracting the second equation from the first? <br> -4x-2y=-2<br> x-2y=9

diamong [38]

Answer:

x=2.2

y=-3.4

Step-by-step explanation:

subtract the second from the first

-5x=-11

x=2=2

substituting by x in the first equation

so y=-3.4

6 0

2 years ago

The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the pro

Bogdan [553]

Answer:

Step-by-step explanation:

Let X be the length of pregnancy.

X is N(268, 15)

a) Prob of pregnancy lasting 307 days or longer

= P(X>307) = $P(Z>\frac{307-268}{15} )\\=P(Z>2.6)\\$

=0.5-0.4953

=0.0047

b) Lowest 2% is 2nd percentile

Z=-2.55

X score = 268-2.55(15)

= 229.75 days

If length of days >230 days then it is not premature.

4 0

2 years ago