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VMariaS [17]
3 years ago
5

Two classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the lar

ger class.
Mathematics
1 answer:
elena-s [515]3 years ago
8 0
Well if the  1 st two classes have 25 each and 25 and 25 is 50 all together then the larger class is 25 + 6 = 31
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mote1985 [20]

The number of passengers that :

  • Needs Transfer only = 13 passengers
  • Are going to work only = 17 passengers

Let :

Passengers that needs transfer = T = 35

Passengers going to work, W = 39

Passengers who do not need transfers and aren't going to work = 12

Using a venn diagram :

Let the Passengers who do not need transfers and are going to work and needs transfer = x

Passengers who need transfer only = 35 - x

Passengers who are going to work only = 39 - x

To find x :

35 - x + 39 - x + x + 12 = 64

86 - x = 64

-x = 64 - 86

-x = - 22

x = 22

the number of passengers that need transfers but aren’t going to work will be = 35 - 22 = 13 passengers

the number of passengers that are going to work but do not need transfers will be : 39 - 22 = 17 passengers

Learn more : brainly.com/question/1605100?referrer=searchResults

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3 years ago
I already did 1,2 I just need help with three I’ll give u the best rating if u can answer it ❤️
nordsb [41]

Answer:

125in³

Step-by-step explanation:

A box that would perfectly fit the bowling ball will be a cube shape.

The box will have the dimensions 5in by 5in by 5in. These dimensions come from the diameter for the ball.

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V = s³

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Create a sequence in which 1 1/4 is added to each number
RSB [31]
1/4 1/2 3/4 1 1 1/4 1 1/2 1 3/4 2...
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3 years ago
Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.
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Answer:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is ar^{n-1}

Therefore the sum of the first n terms is:

\Sigma_{k=1}^{n}(ar^{k-1})

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

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