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VMariaS [17]
3 years ago
5

Two classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the lar

ger class.
Mathematics
1 answer:
elena-s [515]3 years ago
8 0
Well if the  1 st two classes have 25 each and 25 and 25 is 50 all together then the larger class is 25 + 6 = 31
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Which rate is faster:a bird traveling at a constant rate of 2 kilometer per hour or an insect travelinf at a constant rate of 1,
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The bird since 1 kilometer is 1000 meters
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3 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
She determined that the food court is at point (1, 1), the restrooms are at point (4, 3), the candy shop is at point (-6, 1), th
Butoxors [25]
B) the food court and the boutique.   &
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8 0
3 years ago
A tortoise and a hare are competing in a 2000-meter race. The arrogant hare decides to let the tortoise have a 550-meter head st
andrew-mc [135]

Answer:

a) distance covered by hare d1 = 8t

b) distance covered by tortoise d2 = 5t + 550

c) ∆d = 550 - 3t

Step-by-step explanation:

Given;

Speed of hare u = 8m/s

Speed of tortoise v = 5 m/s

Initial distance of tortoise d0 = 550 m

a) using the equation of motion;

distance covered = speed × time + initial distance

d = vt + d0

For hare;

d0 = 0

Substituting the values;

d1 = 8t + 0

d1 = 8t

b)using the equation of motion;

distance covered = speed × time + initial distance

d2 = vt + d0

For tortoise;

d0 = 550m

Substituting the values;

d2 = 5t + 550

d2 = 5t + 550 m

c) the number of meters the tortoise is ahead of the hare.

∆d = distance covered by tortoise - distance covered by hare

∆d = d2 - d1

Substituting the values;

∆d = (5t + 550) - 8t

∆d = 550 - 3t

6 0
3 years ago
Please help me!<br><br> Decrease £40 by 10%
Alekssandra [29.7K]

Answer:

36

Step-by-step explanation:

40 * .10 = 4

40-4 = 36

6 0
3 years ago
Read 2 more answers
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