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2 years ago

Help me please. What is (2a+8) + (4a +5)

Mathematics

2 answers:

Rom4ik [11]2 years ago

8 0

Answer:

6a + 13

Step-by-step explanation:

2a + 4a = 6a

8 + 5 = 13

6a + 13

Nutka1998 [239]2 years ago

6 0

Answer: 6a+13

Step-by-step explanation:

2a+8+4a+5

2a+13+4a

now combine like terms:

2a+13+4a=

6a+13

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Identify the missing term in the following geometric sequence:

aleksley [76]

Answer:

B. -1/8

Step-by-step explanation:

Using the terms given in the sequence:

4, -2, 1, -1/2, 1/4

we can find the pattern by dividing since it is a geometric seqence:

-2/4 = -1/2

1/-2 = -1/2

-1/2 ÷ 1 = -1/2

So, each term is multiplied by -1/2 to get the next term in the sequence:

$\frac{1}{4}*-\frac{1}{2}=-\frac{1}{8}$

3 0

3 years ago

He weighs 88.9 kg. How many grams is this?

Serhud [2]

A kilogram is 1000 grams, so 88.9 x 1000 = 88,900 grams.

6 0

3 years ago

Read 2 more answers

What is the surface area of a sphere with radius of 3.5? A. 12.25p B. 14p C. 24.5p D. 49p

Anuta_ua [19.1K]

S=4πr2 - this is the equation for the surface area of a sphere. We know that the radius (r) is 3.5 so here's how to solve this:

S = 4π r2
S = 4π (3.5)2
S = 4π 12.25
S = 49π

The surface area of a sphere with radius of 3.5 is 49π.

7 0

3 years ago

Given f(x) = -* - - 5, solve for x when f(x) = -3.

Ne4ueva [31]

Answer:

x = -2

Step-by-step explanation:

Step 1: Define

f(x) = -x - 5

f(x) = -3

Step 2: Substitute and Evaluate

-3 = -x - 5

2 = -x

x = -2

7 0

3 years ago

Read 2 more answers

A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi

viktelen [127]

Answer:

Side length = $\sqrt{\frac{A}{3} }$ cm , Height = $\frac{1}{2} \sqrt{\frac{A}{3} }$ cm , Volume = $\frac{A\sqrt{A}}{6\sqrt{3} }$ cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

$y = \frac{A - x^{2} }{4x}$

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( $\frac{A - x^{2} }{4x}$ )

V = $\frac{Ax - x^{3} }{4}$

To find max volume put V' = 0

So taking derivative equation becomes

$\frac{A - 3 x^{2} }{4} = 0$

A = 3 $x^{2}$

$x^{2}$ = $\frac{A}{3}$

x = $\sqrt{\frac{A}{3\\} }$

put value of x in equation 1

y = $\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }$

y = $\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }$

y = $\frac{1}{2} \sqrt{\frac{A}{3} }$

So the volume will be

V = $x^{2}$ × y

Put values of x and y from equation 2 & 3

V = $\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )$

V = $\frac{A\sqrt{A}}{6\sqrt{3} }$

8 0

3 years ago