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Setler [38]
2 years ago
10

What is 4347 divided by 25 and explain how you got your answer

Mathematics
1 answer:
krok68 [10]2 years ago
8 0

Answer:

173.88 or 173\frac{22}{25}

Step-by-step explanation:

Look at photo attached.

Hope this helpsʕ•ᴥ•ʔ

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The equations of four lines are given. Identify which lines are parallel.
Stella [2.4K]
Lines 2 & 3 are parallel.
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2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
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−3 = −6 + 9<br> 2 + 4 = 12 can anybody help me with this ?
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Step-by-step explanation:

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2 years ago
Wrote an expression gor <br> m &lt; RST
grigory [225]

The expression for the angle m∠RST from the given bisctor is; 6x - 18

<h3>How to find the expression for a given angle?</h3>

From the given image in the attachment we are given that;

SQ bisects ∠TSR

m ∠RSQ = 3x - 9

Now, since  SQ is a bisector of ∠TSR, we can say that

m∠RST = 2 * m∠RSQ

Thus angle RST is expressed as;

m∠RST = 2(3x - 9)

m∠RST = 6x - 18

Read more about Angle expression at; brainly.com/question/16953095

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1 year ago
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