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Goshia [24]
2 years ago
11

A thief steals an atm card and must randomly guess the correct five-digit pin code from a 8​-key keypad. repetition of digits is

allowed. what is the probability of a correct guess on the first​ try?
Mathematics
1 answer:
OLEGan [10]2 years ago
8 0

Answer:

The probability of a correct guess on the first try is 0.024%.

Since a thief steals an atm card and must randomly guess the correct four -digit pin code from a 8 -key keypad, and repetition of digits is allowed, to determine what is the probability of a correct guess on the first try the following calculation must be performed:

8 x 8 x 8 x 8 = X

8 ^ 4 = X

4096 = X

1/4096 = X

0.000244140625 = X

0.000244140625 x 100 = 0.024%

Therefore, the probability of a correct guess on the first try is 0.024%

Step-by-step explanation:

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Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th
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Answer:

P(X = 0) = 0.0263

P(X = 1) = 0.1407

P(X = 2) = 0.3012

P(X = 3) = 0.3224

P(X = 4) = 0.1725

P(X = 5) = 0.0369

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 5, p = 0.517

Distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263

P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407

P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012

P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224

P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725

P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369

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