The answer is 4.27 if it’s the blue painted ones
Answer:
<u>∠DFA = 82°</u>
Step-by-step explanation:
According the property of inscribed angles and arcs, the angle is half of the arc length.
Solving :
- ∠CFB = 1/2 x ∡CB
- ∠CFB = 1/2 x 164°
- ∠CFB = 82°
- ∠CFB = ∠DFA (Vertically Opposite Angles)
- <u>∠DFA = 82°</u>
Answer:
A and D and E
Step-by-step explanation:
Substitute the variable(in this case) <em>t</em> for 3, then use the order of operations to simplify(PEMDAS), which will give you 33 for both expressions. To see if two expressions are equivalent, you need to substitute the variable for an odd number AND an even number, so next, substitute the variable <em>t </em>for the number 6, which will give you 51 for both expressions. That means the expressions are equivalent
Hope this helps :)
P.S. Mark brainliest pls
I believe it is -20.
Hope that helped you out.
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
