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Fudgin [204]
3 years ago
15

Marcus has 127 baseball cards in his collection. Gabriel has 56 cards in his collection. Gabriel divides his collection evenly a

mong Marcus and 7 other friends. How many baseball cards does Marcus have now?
Use the drop-down menu to show the correct answer.

Marcus has
Choose...
baseball cards now.
Mathematics
1 answer:
Kryger [21]3 years ago
8 0

Answer:

134

Step-by-step explanation:

Gabriel has 56 cards and divides them evenly among 8 friends, which means each person has 56/8= 7 cards.

So Marcus has 127 + 7 = 134 cards

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in the diagram, a building casts a 35-ft shadow and a flagpole casts a 10-ft shadow. if the flagpole is 22tall, how tall is the
8_murik_8 [283]

Let, the height of the building be x ft.

Given the building casts 35ft shadow.

The height of the flagpole given which is 22ft and casts a shadow of 10ft.

Now to find the height of the building we have to equate the ratio of height and shadow of the building and the flagpole.

So we can write,

x/35 = 22/10

To find x, we have to get rid of 35 from the left side and have to move it to right side. As 35 is divided there, we will multiply 35 to both sides.

(x/35)× 35 = (22/10)×35

x = (22×35)/10

x = 770/10

x = 77

So, the height of the building is 77 ft which is the required answer here.

8 0
3 years ago
In square YOLA, RL=5x+28 and RO=8X-11
Alexeev081 [22]

Answer:

RL=5x+28 and

RO=8X-11

diagonal of square bisect equally the side

:.5x+28=8x-11

11+28=8x-5x

39=3x

x=39/3=13

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6 0
3 years ago
Use the point P(3, —6). Write the ordered pair for the final location of the given point after completing the transformations in
sashaice [31]

Answer:Go on a graph calolator

Step-by-step explanation:

calul

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Ctan%28x%20%29%20%20%3D%20%20%5Cfrac%7B10%7D%7B60%7D%20" id="TexFormula1" title=" \tan(x
chubhunter [2.5K]

tan(x) = 10/60

tan(x) = 1/6

tan(x) = a -> x = arctan(a) + πn

x = arctan(1/6) + πn

x = 0.165 + πn

Best of Luck!

7 0
4 years ago
Im bored in this quarentine and have a lot of work to catch up on. One of my math problems is "How much water should be added to
Kazeer [188]

Answer:

20/3  ounces of water is added.

Step-by-step explanation:

how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?

--------------

The acid is 40% of 20 ounces = 8 ounces.

0.4*20 = 8

----------

 

That same 8 ounces is to be 30%. The water will be the other 70%.

8/30 = x/100

30x = 800

x = 80/3, the total amount of the solution.

We started with 20, so 80/3 - 20 = 20/3

20/3 ounces of water is added.

8 0
3 years ago
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