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2 years ago

Find the value of x and y of the equilateral triangle. I need it ASAP

Mathematics

1 answer:

katrin2010 [14]2 years ago

7 0

Answer:

x=12, y=30

Step-by-step explanation:

to find x:

in a equilateral triangle, all three sides are congruent, so:

4x-4=3x+8

x-4=8

x=12

to find y:

in an equilateral triangle, all the angles are 60°, so:

2y=60

y=30°

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Find the sum of the first 9 terms of the following series, to the nearest integer.

Arturiano [62]

367 is the best answer I came up with

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2 years ago

Factor 8X squared + 10x + 2

mojhsa [17]

Answer:

2(4x + 1)(x + 1)

Step-by-step explanation:

Given

8x² + 10x + 2 ← factor out 2 from each term

= 2(4x² + 5x + 1)

To factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × 1 = 4 and sum = + 5

The factors are + 1 and + 4

Use these factors to split the x - term

4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )

= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)

= (4x + 1)(x + 1), thus

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8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form

3 0

3 years ago

What is the length of BC in the right triangle below 21 and 72

sleet_krkn [62]

Im guessing 21 and 72 are the side lengths for the triangle?

Alright, so since it's a right triangle you can use the Pythagorean theorem or a^2+b^2=c^2

Since i cant see the picture, im going to use some general math so i can figure out if those two sides are the legs or if one of them is the hypotenuse
Alright
so im guessing the side we're trying to find is the hypotenuse

21^2+72^2=c^2
441+5184=c^2
5625=c^2
√5625=c
75=c

The answer is 75, hope i helped!

3 0

2 years ago

13x−2= − 10 x − 2 −10x−2

Misha Larkins [42]

Answer:

x=0

Step-by-step explanation:

13x-2 = 10x-2

Subtract 10x from each side

13x-10x-2 = 10x-2 -10x

3x-2 = -2

Add 2 for each side

3x-2+2 = -2+2

3x= 0

divide by 3

3x/3 = 0/3

x =0

3 0

3 years ago

PLEASE HELP 20 POINTS solve the system of equations y=-5x-7 and -4x-3y=-1 by substitution.

Ainat [17]

Answer:

Solution: x = -2; y = 3 or (-2, 3)

Step-by-step explanation:

Equation 1: y = -5x - 7

Equation 2: -4x - 3y = -1

Substitute the value of y in Equation 1 into the Equation 2:

-4x - 3(-5x - 7) = -1

-4x +15x + 21 = -1

Combine like terms:

11x + 21 = - 1

Subtract 21 from both sides:

11x + 21 - 21 = - 1 - 21

11x = -22

Divide both sides by 11 to solve for x:

11x/11 = -22/11

x = -2

Now that we have the value for x, substitute x = 2 into Equation 2 to solve for y:

-4x - 3y = -1

-4(-2) - 3y = -1

8 - 3y = -1

Subtract 8 from both sides:

8 - 8 - 3y = -1 - 8

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Divide both sides by -3 to solve for y:

-3y/-3 = -9/-3

y = 3

Therefore, the solution to the given systems of linear equations is:

x = -2; y = 3 or (-2, 3)

Please mark my answers as the Brainliest if you find this helpful :)

7 0

2 years ago