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Dimas [21]
3 years ago
6

5. Jason is ordering a kids meal. He can

Mathematics
1 answer:
Advocard [28]3 years ago
3 0
Yo thanks dude for the 25 point it’s generous :)
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The answer should be 2 p.m. .
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Mrac [35]

The function y = - 50x + 75 is linear. So, the correct option is (A).

<h3>Define linear function.</h3>

The formula for a linear function is f(x) = mx + b, where m and b are real values. Isn't it resembling the slope-intercept form of a line, represented by the equation y = mx + b? Yes, this is the case as the graph of a linear function is a line. Here,

The line has a slope of m and a y-intercept of b.

The independent variable is "x."

The dependent variable is "y" (also known as f(x)).

Consider the equation y = - 50x + 75

Compared to the linear function equation, we get

m = -50

b = 75

So, the function is a linear function with a constant change. The function will be linear at all points.

To know more about linear functions, visit:

brainly.com/question/20286983

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2 years ago
Which set of numbers is ordered from least to greatest?
snow_lady [41]
The set of numbers running from least to greatest is C.
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4 years ago
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oksian1 [2.3K]

Answer:

t= 6\ s

Step-by-step explanation:

We know that the equation that models the height of the ball as a function of time is h(t) = -16t ^ 2 + 80t + 96.

Where the initial speed is 80 feet.

When the ball lands on the ground, its height will be h(t) = 0.

So to know how long it will take the ball to reach the ground, equal h (t) to zero and solve for t.

-16t ^ 2 + 80t + 96 = 0

To solve this quadratic equation we use the quadratic formula.

For an equation of the form:

at^2 +bt +c

The quadratic formula is:

t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}

In this case

a =-16\\b = 80\\c =96

Then

t=\frac{-80\±\sqrt{80^2 -4(-16)(96)}}{2(-16)}

t_1=-1\\\\t_2=6

We take the positive solution

t= 6\ s

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3 years ago
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Aricela is trying to estimate the distance between her house and the park. On a map with a ascake if 0.5 in. = 2 miles, the dist
pochemuha

Answer:

only 34

Step-by-step explanation:

and then you oh

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