Complete question :
Tom will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $57.98 and costs an additional $0.14 per mile driven. The second plan has an initial fee of $53.98 and costs an additional $0.16 per mile driven. How many miles would Tom need to drive for the two plans to cost the same?
Answer:
200 miles
Step-by-step explanation:
Let miles driven = x
First option :
57.98 + 0.14x
Second option :
53.98 + 0.16x
First option = second option
57.98 + 0.14 = 53.98 + 0.16x
57.98 - 53.98 = 0.16x - 0.14x
4 = 0.02x
x = 200
200 miles
Answer:
Step-by-step explanation:
From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (
) and are parallel to 
The parallel vector to the line i + zj+k = ai + bj + ck
Hence, the equation for the line is :
x = 4 + t
y = -5 + 2t
z = 2 + t
Thus, x, y, z = ( 4+t, -5+2t, 2+t )
The symmetric equation can now be as follows:
∴
|x| because just Google it if I'm wrong
So I believe you will have to do 10% x 7 as it has been seven years which will be 70% and 70% of 8000 is 5600 so the answer will be £5600
I don't understand your language and I don't know which language is this but I try to answer your question. 3-1000-3*100*4*1
3-1000-1200
3-2200
=-2197
