91, I just kept adding 5 until I got to the 20th term
Answer: 5,499,187,200
<u>Step-by-step explanation:</u>
A coin is tossed 5 times.
There are two options (heads or tails) so the possible outcomes are: 2⁵
A six-sided die is rolled 4 times.
There are six options so the possible outcomes are: 6⁴
A group of 3 cards are drawn (without replacement).
The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50
Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:
2⁵ x 6⁴ x 52 x 51 x 50
= 32 x 1296 x 132,600
= 5,499,187,200
Answer:
The sum of the first 37 terms of the arithmetic sequence is 2997.
Step-by-step explanation:
Arithmetic sequence concepts:
The general rule of an arithmetic sequence is the following:
In which d is the common diference between each term.
We can expand the general equation to find the nth term from the first, by the following equation:
The sum of the first n terms of an arithmetic sequence is given by:
In this question:
We want the sum of the first 37 terms, so we have to find 
Then
The sum of the first 37 terms of the arithmetic sequence is 2997.
Answer:
[22 x 21] / 2=231 or "c"
Step-by-step explanation:
Hello,
The answer is option B "false".
Reason:
The answer is false because the volume can be measure in anyway for example: feet, yards.
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
