Answer: Hope it helps :)
<u>-4</u>
7
Step-by-step explanation:
You have to use the formula <u>y2-y1</u>
x2-x1
So <u>-4-4</u>
8--6
-4-4= -8
8--6= 14 (two negative signs become a positive sign)
You have -8 over 14
If you simplify it's -4/7 or <u>-4</u>
7
Answer:
it's
2.08
Step-by-step explanation:
<em><u>
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<em><u>so</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>think</u></em><em><u> </u></em><em><u>think</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u>f</u></em><em><u>u</u></em><em><u>l</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em>2</em><em>.</em><em>0</em><em>8</em>
Answer:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
Step-by-step explanation:
Use the method for solving Bernoulli equations to solve the following differential equation.
StartFraction dy Over dx EndFraction plus StartFraction y Over x minus 9 EndFraction equals 5 (x minus 9 )y Superscript one half
Answer:
Step-by-step explanation:
a)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,r =50
rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854
area growing 7854 cm2/s
b)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,A =64
pi r^2 =64
=>r =8/√pi
rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98
area growing 708.98 cm2/s
Answer:
C. Median
Step-by-step explanation:
If both sides are <em>symmetrical,</em> then there is no need to try and find the mean or anything because you already have the middle point and no outliers. <u>If there were outliers it'd be different</u>, unless the outliers were symmetrical with the rest of it, then the median would still be a good option.
