Answer:
20 + 0.05x ≥ 65
Step-by-step explanation:
20 is by itself since thats what he earns extra per day.
Since he earns 0.05 per flyer, that means we are going to need a variable since we don't know how many flyers he passes. Let x be equal to that.
Since he wants to make at LEAST 65 we are going to use the greater than or equal to symbol since he doesn't want to make less than that.
20 + 0.05x ≥ 65
Best of Luck!
Answer:
10. 7n - 1 < -8
Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:
7n - 1 (+1) < - 8 (+1)
7n < - 8 + 1
7n < - 7
Isolate the variable, n. Divide 7 from both sides:
(7n)/7 < (-7)/7
n < -7/7
n < -1
n < -1 is your answer.
11. 3 > -7v + 4v
Combine like terms, then isolate the variable, v. First, add -7v and 4v together.
3 > (-7v + 4v)
3 > (4v - 7v)
3 > (-3v)
Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:
(3)/-3 > (-3v)/-3
3/-3 > v
-1 < v
v > -1 is your answer.
~
Answer: r= -3
Next 3 terms following 54 are -162, 486, -1458
Step-by-step explanation:
Answer:
the side s is 18
Step-by-step explanation:
s=?
Area of square(A)=324
Now,
A=s²
324=s²
√(324)=s
s=18
Answer:
For 3x^2+4x+4=0
Discriminant= = -32
The solutions are
(-b+√x)/2a= (-2+2√-2)/3
(-b-√x)/2a= (-2-2√-2)/3
For 3x^2+2x+4=0
Discriminant= -44
The solutions
(-b+√x)/2a= (-1+√-11)/3
(-b-√x)/2a= (-1-√-11)/3
For 9x^2-6x+2=0
Discriminant= -36
The solutions
(-b+√x)/2a= (1+√-1)/3
(-b-√x)/2a= (1-√-1)/3
Step-by-step explanation:
Formula for the discriminant = b²-4ac
let the discriminant be = x for the equations
The solution of the equations
= (-b+√x)/2a and = (-b-√x)/2a
For 3x^2+4x+4=0
Discriminant= 4²-4(3)(4)
Discriminant= 16-48
Discriminant= = -32
The solutions
(-b+√x)/2a =( -4+√-32)/6
(-b+√x)/2a= (-4 +4√-2)/6
(-b+√x)/2a= (-2+2√-2)/3
(-b-√x)/2a =( -4-√-32)/6
(-b-√x)/2a= (-4 -4√-2)/6
(-b-√x)/2a= (-2-2√-2)/3
For 3x^2+2x+4=0
Discriminant= 2²-4(3)(4)
Discriminant= 4-48
Discriminant= -44
The solutions
(-b+√x)/2a =( -2+√-44)/6
(-b+√x)/2a= (-2 +2√-11)/6
(-b+√x)/2a= (-1+√-11)/3
(-b-√x)/2a =( -2-√-44)/6
(-b-√x)/2a= (-2 -2√-11)/6
(-b-√x)/2a= (-1-√-11)/3
For 9x^2-6x+2=0
Discriminant= (-6)²-4(9)(2)
Discriminant= 36 -72
Discriminant= -36
The solutions
(-b+√x)/2a =( 6+√-36)/18
(-b+√x)/2a= (6 +6√-1)/18
(-b+√x)/2a= (1+√-1)/3
(-b-√x)/2a =( 6-√-36)/18
(-b-√x)/2a= (6 -6√-1)/18
(-b-√x)/2a= (1-√-1)/3
