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labwork [276]
2 years ago
13

The problem is write you answer using ONLY positive exponents

Mathematics
1 answer:
Fed [463]2 years ago
5 0

Answer:

z^10/z^5 = z^5

Step-by-step explanation:

if it is divide, you minus, so z^10/z^5 is z^5.

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What is the probability of these events when we randomly select a permutation of {1,2, ..., n} where n≥4? a) 1 precedes 2 c) 1 i
Paraphin [41]

Answer:

a) 1/2

b) 1/n

c) 1/4

Step-by-step explanation:

a) For each permutation, either 1 precedes 2 or 2 precedes 1. For each permutation in which 1 precedes 2, we can swap 1 and 2 to obtain a permutation in which 2 preceds 1. Thus, half of the total permutations will involve in 1 preceding 2, hence, the probability for a permutation having 1 before 2 is 1/2.

c) If 2 is at the start of the permutation, then it is impossible for 1 to be before 2. If that is not the case, then 1 has a probability of 1/n-1 to be exactly in the position before 2. We can divide in 2 cases using the theorem of total probability,

P( 1 immediately preceds 2) = P (1 immediately precedes 2 | 2 is at position 1) * P(2 is at position 1) + P(1 immediately precedes 2 | 2 is not at position 1) * P(2 is not at position 1) = 0 * 1/n + (1/n-1)*(n-1/n) = 1/n.

d) We can divide the total of permutations in 4 different groups with equal cardinality:

  • Those in which n precedes 1 and n-1 precedes 2
  • those in which n precedes 1 and 2 precedes n-1
  • those in which 1 precedes n and n-1 precedes 2
  • those in which 1 precedes n and 2 precedes n-1

All this groups have equal cardinality because we can obtain any element from one group from another by making a permutations between 1 and n and/or 2 and n-1.

This means that the total amount of favourable cases (elements of the first group) are a quarter of the total, hence, the probability of the event is 1/4.

3 0
3 years ago
Last year, an orange tree produced 36 oranges. This year, it produced fewer than 10. What are the possible values for how many f
weeeeeb [17]

Answer:

d : [ 0 , 26 ]

Step-by-step explanation:

Given:-

- The oranges produced last year, x = 36

- The oranges produced this year, y < 10

Find:-

What are the possible values for how many fewer oranges were produced from the tree this year

Solution:-

- The possible values for how many fewer oranges were produced this year relative to last can be determined by solving an inequality that signifies a difference (d) between last year and this year production as follows:

                                 d = x - y

                                 d = 36 - (<10)

- To remove the inequality from Right hand side we we can shift it to left hand side by inverting the inequality sig, since last production is exactly known we have:

                                d≥36 - 10

                                d≥ 26

- So the number of oranges produced are at least 26 less than last year and lower bound would be if there is no orange produced this year. Hence, the range is:

                               d : [ 0 , 26 ]                          

4 0
3 years ago
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