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kolezko [41]
2 years ago
14

Common household electric current is called alternating current because the current alternates direction within the wires. The v

oltage V in a typical​ 115-volt outlet can be expressed by the function V(t)=163 sin wt Upper V left parenthesis t right parenthesis equals 163 sine omega t
​,





where omega=w






is the angular speed​ (in radians per​ second) of the rotating generator at the electrical plant and t is the time measured in seconds. It is essential for electric generators to rotate at precisely 60 cycles per sec.






How many times does the current oscillate in 0.30






​sec?__times
Mathematics
1 answer:
Rainbow [258]2 years ago
5 0

Answer:

n = 18 cycles

Step-by-step explanation:

To know how many times does the current oscillates in the given time, you take into account that the number of oscillation can be calculated by using the following expression:

n=ft         (1)

f: frequency of the oscillation of the current

t: time = 0.30s

The frequency is the number of cycles per second, that is, f = 60 cycles/s

You replace the values of f and t in the equation (1):

n=(60\frac{cycles}{s})(0.30s)=18\ cycles

In 0.30s the current oscillates 18 times

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A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten
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Answer:

<em>35.11 ft</em>

<em></em>

Step-by-step explanation:

This given situation can be thought of as triangle \triangle PQR where PQ is the length of pole.

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and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And \angle Q \neq 90^\circ

Given that:

PQ = 44 ft

PR = 51 ft

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To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}

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\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ

Now,

\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ

Let us use the Sine rule again:

\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft

So, the answer is <em>35.11 ft</em>.

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