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uranmaximum [27]
2 years ago
14

Find the derivative of the image below

Mathematics
1 answer:
Nata [24]2 years ago
3 0

~~~\dfrac{d}{dx} f(x)  \\ \\=\dfrac{d}{dx} \left(x^3 \cdot \log_6 x \right)\\\\=x^3\dfrac{d}{dx} \left(\log_6 x\right) + \log_6 (x)\dfrac d{dx} x^3 \\\\=x^3 \cdot \dfrac 1{x \ln 6} + \log _6 (x) \cdot 3x^2\\\\=\dfrac{x^2}{\ln 6} + \log_6(x) \cdot 3x^2\\\\\\=x^2 \left(\dfrac 1{\ln 6} + 3\log_6 x \right)

\text{The derivative  is  now in a  form of}~ x^A (B  + C \log_D (x))

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Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...
timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

a_1=-36

now, we can find common ratio

r=\frac{6}{-36}

r=-\frac{1}{6}

now, we can find nth term

a_n=a_1(r)^{n-1}

now, we can plug values

and we get

a_n=36(-\frac{1}{6})^{n-1}

now, we can find 5th term , 6th term, 7th term

fifth term:

a_5=36(-\frac{1}{6})^{4}

a_5=\frac{1}{36}

sixth term:

a_6=36(-\frac{1}{6})^{5}

a_6=-\frac{1}{216}

seventh term:

a_7=36(-\frac{1}{6})^{6}

a_7=\frac{1}{1296}

so, next terms are

a_5=\frac{1}{36} , a_6=-\frac{1}{216}

, a_7=\frac{1}{1296}.............Answer

6 0
3 years ago
The equation of function h is h(x) = 1/2(x - 2)^2. The table shows some of the values of function m.
PtichkaEL [24]

Answer:duuno i wanted to help

Step-by-step explanation:

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3 0
3 years ago
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4 years ago
At lunchtime, a cafeteria served a total of 3/8 of a pot of chicken soup and 7/8 of a pot of
Effectus [21]
Answer:

1 1/4

reason:

add 7/8 and 3/8 to get 10/8
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7 0
3 years ago
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6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0
3 years ago
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