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Alla [95]
3 years ago
12

Find sin0, cos0, tan0

Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0

Answer:

sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5

Step-by-step explanation:

We need to find sine, cosine, and tangent of theta for this triangle.

First, define the different trigonometric functions:

- sine is opposite side to the angle divided by the hypotenuse (longest side not adjacent to the 90 degree angle)

- cosine is the adjacent side next to the angle divided by the hypotenuse

- tangent is the opposite side to the angle divided by the adjacent side

Now, look at theta (θ):

- the opposite side is marked 12

- the adjacent side is marked 5

- the hypotenuse is marked 13

So:

- sin(θ) = opposite / hypotenuse = 12/13

- cos(θ) = adjacent / hypotenuse = 5/13

- tan(θ) = opposite / adjacent = 12/5

Thus the answers are: sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5.

chubhunter [2.5K]3 years ago
5 0

Answer:

sin(theta) = 12/13

cos(theta) = 5/13

tan(theta) = 12/5

Step-by-step explanation:

sin(theta) = opposite/hypotenuse

12/13

cos(theta) = adjacent/hypotenuse

5/13

tan(theta) = opposite/adjacent

12/5

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Image below

Step-by-step explanation:

<em>Given: Side lengths of a right triangle 3,4 and 5 units. </em>

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