The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF
Answer:
= 3n + 4
Step-by-step explanation:
there is a common difference between consecutive terms , that is
10 - 7 = 13 - 10 = 16 - 13 = 3
this indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 7 and d = 3 , then
= 7 + 3(n - 1) = 7 + 3n - 3 = 3n + 4
Answer:
what is the question you are trying to answer? leave a comment below and I will try to answer it .
Step-by-step explanation:
Answer:
ive been trying to figure out your question i just cant lol. I understand why you put it on here lol. Im so sorry
Step-by-step explanation:
