The vertex of the parabola is (-3, 9)
In order to find the vertex of any quadratic, you start by finding the x-value of said vertex. This can be done using the equation below.
-b/2a
In this equation 'a' refers to the coefficient of x^2 (-1) and 'b' refers to the coefficient of x (-6). So then we can plug into that equation using those values.
-b/2a
-(-6)/2(-1)
6/-2
-3
Now that we have the x value, we can substitute that value into the equation to find the y value.
f(x) = -x^2 - 6x
f(x) = -(-3)^2 - 6(-3)
f(x) = -(9) + 18
f(x) = 9
Therefore our point is (-3, 9)
Answer:
12
Step-by-step explanation:
Step-by-step explanation:
Excuse me, what is your question ?
Answer:
bbbbbbbbbbbbbbbbbbbbbbbbb
Assuming
![g(x)=3 \sqrt{x-5}+7](https://tex.z-dn.net/?f=g%28x%29%3D3%20%5Csqrt%7Bx-5%7D%2B7%20%20)
and parent function is
![3 \sqrt{x}](https://tex.z-dn.net/?f=3%20%5Csqrt%7Bx%7D%20%20)
to move a function up c units, add c to whole function
to move a function to right c units, minus c from every x
7 was added to whole function and 5was mnused from every x
moved 7 up and 5 to right
2nd option