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daser333 [38]
2 years ago
7

Write the equation of a line perpendicular to y= -1/3x + 5 and passes through the point (6, 4).

Mathematics
1 answer:
Levart [38]2 years ago
3 0

Answer:

y = 3x - 14

Step-by-step explanation:

Perpendicular lines will have a opposite reciprocal slope, so the slope will be 3.

Plug in the slope and given point into y = mx + b, then solve for b:

y = mx + b

4 = 3(6) + b

4 = 18 + b

-14 = b

Plug in the slope and y intercept into y = mx + b

y = 3x - 14

So, the equation of the line is y = 3x - 14

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Answer:

A) x = 3 or -1

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Step-by-step explanation:

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Rearranging, we have;

2x² - x² - 2x - 2 - 1 = 0

x² - 2x - 3 = 0

Using quadratic formula, we have;

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x = (2 ± √16)/2

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Multiply through by 15 to get;

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log(2x + 3) = logx²

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x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

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